Return to MENU Back Activity 6 - Regular PolygonsThis Activity and the related Essays on the History of Mathematics are on-line at MATHGYM (http://www.mathtrak.com.au/mic/)
Definition - "Polygon" is a Greek word meaning "many sides." The regular polygon is a convex plane shape (fills a flat surface) which has all of its sides the same length, and all its internal angles the same size. There are an infinite number of these. We will investigate some of the properties of these shapes below.
In this activity we will find the relationship between the number of sides of a polygon and its internal angles. To do this you should use the first four regular polygons to complete the table below. After you have completed the pentagon and hexagon rows you should try to find a pattern. Then complete the last row for a polygon of n sides.
Activity B:
In this activity we will investigate which regular polygons "fill the plane at a point" or tessellate the plane.
Complete this sentence, summarising your findings: "The shapes ..............., ............., and ............... fill the plane at a point".
Look at the internal angles of each of the regular polygons which "fill the plane at a point". Use these angles to explain why these shapes "fill the plane" but the pentagon and heptagon don't?
Do you think that any other polygons will "fill the plane at a point"? Make a conjecture . Try to prove your conjecture for all regular polygons.
My summary reads "The shapes equilateral triangle, square, and hexagon "fill the plane at a point".
I notice that all the shapes which "fill the plane" have internal angles (60, 90, 120) which divide evenly into 360 degrees. The pentagon and heptagon have internal angles (108, 900/7) which don't divide evenly into 360 degrees.
My conjecture is: "Only the equilateral triangle, square, and hexagon "fill the plane at a point".
We have tested the five polygons and found that the equilateral triangle, square, and hexagon work. This is because their internal angles are factors of 360 degrees (the size of the revolution angle at the point).
Below is a different proof for my conjecture for those readers who know algebra.
Now must be a whole number. We can make a table to see the possible solutions for n.
From ths table we can see that the only possible whole number values for n are 3, 4, and 6. |